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Dec 17, 2024 · There are 56 ways to form a committee of 3 people from a group of 8. This is calculated using the combinations formula C (n, r). Using the values n = 8 and r = 3, the calculation yields the result of 56.
https://artofproblemsolving.com/wiki/index.php/Committee_forming
Each person can either be in the committee or not in the committee. Since there are two possibilities for each person and each person is independent of every other person, there are committees.
https://www.algebra.com/algebra/homework/Permutations/Permutations.faq.question.399184.html
If it is the first way (order doesn't matter) then you need the number of combinations of 8 things taken 3 at a time. On the other hand, if order matters, then you need the number of permutations of 8 things taken 3 at a time.
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Feb 16, 2017 · The number of ways to select a committee of 3 people from 8 candidates is 56, calculated using the combination formula. We applied C (n,r) = r!(n−r)!n!, leading us to simplify the expression and find the result. Therefore, there are 56 different committee selections possible.
https://ph.gauthmath.com/solution/1986566172453764/11-From-a-group-of-8-students-how-many-ways-can-a-committee-of-3-be-chosen-12-A-
We need to choose 3 students from a group of 8. $$C (8, 3) = \frac {8!} {3! (8-3)!} = \frac {8!} {3!5!} = \frac {8 \times 7 \times 6} {3 \times 2 \times 1} = 56$$C (8,3) = 3!(8−3)!8! = 3!5!8! = 3×2×18×7×6 = 56
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Jun 30, 2025 · When a committee of 3 is chosen from 8, normally the number is (38). But if there is a restriction: one person (let's call him A) refuses to serve with another (call them B), any committee containing both A and B is not allowed.
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Nov 25, 2023 · In this case, we have 8 students and we want to select a committee of 3 members. Plugging these values into the formula, we get: C (8, 3) = 8! / (3! (8-3)!) = 8! / (3!5!) = (8 * 7 * 6) / (3 * 2 * 1) = 56 Therefore, there are 56 ways to select a committee of 3 members from a group of 8 students.
https://math.answers.com/other-math/How_many_different_3_person_committees_can_be_formed_from_a_group_of_8
Apr 28, 2022 · In fact, there are 3! or 3x2x1=6 ways to arrange the 3 members so we must divide 8x7x6 by 6 and the result is 56 committees of 3 people picked from 8. Picking a committee is an example...
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A fund-raising committee is to be chosen from a group of 8 students. a. How many ways can a committee of 3 students be chosen? b. How many ways can a committee of 5 students be chosen? SHOW LESS 180
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Mar 24, 2023 · The number of ways to select a committee of 3 from a class of 8 students can be calculated using the formula for combinations, which is: nCk = n! / (k! * (n - k)!)
